Chemical
Equilibrium (chapter 18)
Most
reactions do not go to completion but instead the products can react to re-form
the reactants. These are reversible
reactions. In reversible reactions the
opposing processes eventually occur at the same time and at the same rate. When this happens, the system is in a state
of equilibrium.
For a reversible reaction:
1.
rate expression for the forward reaction: kf[reactants];
rate expression for the reverse
reaction: kr[products]
2. at
equilibrium the forward reaction rate equals the reverse reaction rate:
kf[reactants]
= kr[products] or
and
The Mass-Action Expression
1.
The mass-action expression is used to describe a system undergoing a
chemical change.
2.
The expression is derived from the balanced equation for the
reaction.
A. the
mass-action expression is a fraction formed from the concentrations of the products
in the numerator and the concentrations of the reactants in the
denominator
(products
over reactants)
B.
each concentration is raised to a power indicated by the appropriate
coefficient taken from the balanced equation (coefficients become exponents)
C.
if there is more than one reactant or product, multiply the
concentrations
D. the
density and concentration of pure solids and liquids doesn’t change, therefore
the mass-
action
expression only includes (g) and (aq), do not include (s) or (l)
The Equilibrium Expression and the Equilibrium
Constant
1.
From experimentation, the mass-action expression for a system at
equilibrium shows a constant numerical value at a particular
temperature.
2. When
the mass-action expression is set equal to this constant it is called the
equilibrium
expression
and the constant is called the equilibrium constant, Keq, or K.
This is called the Law of Chemical Equilibrium.
3. For a
general reaction mA + nB Ö sP + rQ ,

4. The
value of the equilibrium constant is not affected by the initial
concentrations, only a change
in
temperature will cause the value to change.
5.
The value of the equilibrium constant indicates the extent to which the
reaction proceeds in the forward
direction (to the right) before reaching an equilibrium.
A. if
Keq > 1, the equilibrium
concentration of the products is relatively large compared with
the
equilibrium concentrations of the reactants
B. if
Keq < 1, the equilibrium
concentration of the reactants is relatively large compared with
the
equilibrium concentrations of the products
Shifting Equilibrium
Le Chatelier's Principle
- when a system is at equilibrium and a stress is applied to that system, the
system reacts to reduce the stress and re-establish equilibrium
Consider an equilibrium reaction like a
see-saw that is balanced: if you change
the weight on either side, the see-saw
becomes unbalanced and you must shift the weight to make it balance again
In
an equilibrium reaction, we can use Le Chatelier's principle to predict which
way the reaction will shift to re-establish equilibrium:
1.
Concentration changes
A. if
you increase the concentration of one of the reactants: reaction shifts to the right and
favors
the forward reaction
B. if
you increase the concentration of one of the products: reaction shifts to the left and favors
the
reverse reaction
C. if
you decrease the concentration of one of the reactants: reaction shifts to the left and favors
the
reverse reaction
D. if
you decrease the concentration of one of the products: reaction shifts to the right and
favors
the forward reaction
2. Pressure
changes - only affect substances that are gases
Pressure
can be change by changing the size of the container:
increase
the volume Õ decrease the pressure; decrease the volume Õ
increase the pressure.
Adding
an inert gas (like neon) won’t have any effect on the pressure of the reactants
or products
because
it doesn’t affect either of them.
A. if
you increase pressure: the reaction
shifts to the side with smaller number of moles (the
side
that the sum of the coefficients is the smallest)
B. if
you decrease pressure: the reaction
shifts to the side with the larger number of moles (the
side
that the sum of the coefficients is the largest)
3. Temperature
changes:
There
are two types of reactions involving temperature, exothermic and
endothermic. An
exothermic
reaction releases heat, this energy can be considered as a product. An endothermic reaction absorbs heat, this energy can be considered as a reactant.
A.
increase the temperature of an exothermic reaction: reaction shifts to the left and favors the reverse
reaction
C. increase
the temperature of an endothermic reaction:
reaction shifts to the right and favors
the
forward reaction
C. decrease the temperature of an exothermic
reaction: reaction shifts to the right
and favors the forward reaction
D.
decrease the temperature of an endothermic reaction: reaction shifts to the left and favors the reverse
reaction
Optimum conditions - conditions that
produce the highest yield of the substance wanted; the
conditions,
such as pressure and temperature and concentrations, that are imposed to shift
the equilibrium position toward that substance according to Le Chatelier's
principle
Reactions
that tend to go to completion include the following:
1. reactions
where a precipitate is formed
2. reactions
where a gas is formed that can escape from the container
3. reactions
where a product is formed that is slightly ionizable
Common
ion effect
What happens if add a
salt that has the ion of the acid?
LeChatelier's Principle: shift equilibrium
positions (the
concentrations change) but the Keq remains the same. The solubility
of a solid is lowered (compared to water) if the solution already contains ions
common to the solid.
Ionization
constant of a weak acid:
Ka, a special case of the equilibrium constant, Keq
for
a weak acid: HA + H2O Ö H3O+1
+ A-1 or HA Ö H+1 + A-1
Keq = [H3O+1].[A-1] / [HA].[H2O] or Keq
= [H+1].[A-1] / [HA]
Ka = Keq.[H2O]
= [H3O+1].[A-1] / [HA] or Ka
= Keq= [H+1].[A-1] / [HA]
Dissociation
(ionization) constant of a weak base: Kb, a special case of the
equilibrium constant, Keq
for
a weak base: B + H2O Ö BH+1
+ OH-1
Keq = [BH+1].[OH-1]
/
[B].[H2O]
Kb = Keq.[H2O]
= [BH+1].[OH-1] / [B]
For any weak acid/base and it's conjugate
base/acid: Ka * Kb
= Kw.
Buffers
1. a buffer is a substance that can absorb
moderate amounts of acid or base without significantly
altering the pH
2. a buffer is a solution of a weak acid and
it's conjugate base or a weak base and it's conjugate
acid (the common ion effect - Le
Chatelier states that the equilibrium shifts but does not change the Keq)
3. buffers are made by:
a.
adding the salt of a weak acid/base to a solution of the weak
acid/base; example: HCH3COO and NaCH3COO and
NH4OH and NH4Cl
4. how buffers work (think of Le Chatelier’s principle: what is there in the solution that
the added substance can combine and how does the equilibrium shift?)
a.
adding a acid to a buffered solution
1. weak
acid buffer: H+1 + A-1
à HA
2. weak base buffer: H+1 + B à
BH+1
b.
adding a base to a buffered solution
1.
weak acid buffer: OH-1
+ HA à A-1
+ H2O
2. weak base buffer: OH-1 + BH+1 à B + H2O
5. Buffering systems are found in many living
organisms where they are responsible for homeostatic control. An example in humans is the blood buffering
system using the HCO3-1.
Ionization of Water - review
Water ionizes only
slightly according to the following equation: H2O(l) Ö H+1 + OH–1 . This
produces equal numbers
of H+1 and OH–1 .
The H+1 that is
produced is very reactive and attaches itself to another water molecule to form
the hydronium ion, H3O+1 . The self ionization of water can now be written as: H2O(l) + H2O(l)
Ö H3O+1 + OH–1.
In
pure water [H+1] = [OH–1] and the solution is
neutral. At 25 ºC these concentrations
have been measured to be [H+1] = [OH–1] = 1.00 x 10–7. Their product is called the ion product
constant of water (or the ionization constant of water) and is given the symbol
Kw and numerically at 25 ºC
is 1.00 x 10–14. Therefore:
[H+1].[OH–1] = 1.00 x 10–14 .
If
you add an acid to a neutral solution, the [H+1] increases and the
[OH–1] decreases so [H+1] > [OH–1] and it is now considered to be an acidic
solution. If you add a base to a
neutral solution, the [OH–1] increases and the [H+1]
decreases so [H+1] < [OH–1] and it is now considered to be a basic solution.
The pH Scale - review
The
pH scale is a simple way to state what the [H3O+1] is in
a solution. It identifies the relative
acidity of the solution. pH is
expressed as a power of ten, usually from 100 to 10-14
.
If [H+1] = [OH–1] = 1.00 x
10–7 is considered neutral than the pH = 7. Definition:
pH = –log10 [H+1].
A known pH value can
be used to find [H+1]. The [H+1] = 10–pH.
The pH scale is usually expressed from 0 to 14. A neutral solution has a pH = 7. An acidic solution has a pH< 7 and a basic solution has a pH >7.
If there is a pH,
there is also a pOH used to state what the [OH–1] is in a
solution.
Definition: pOH = –log10 [OH–1] .
The [OH–1] = 10–pOH.
Mathematically, pH + pOH = 14 .
Hydrolysis of a Salt: Acidic or basic salts
– review
Hydrolysis is the
reaction of a substance with the water that it is dissolved in. Sometimes a salt will react with water to
form an acidic or basic salt. When
acids and bases react, what do they produce?
1. If a strong acid reacts with a strong base, the resulting salt is a neutral salt because the acid and base ionize completely and all of the ions stay as ions.
2.
If a weak acid, HA, reacts with a strong base, the resulting salt is a basic
salt. The anion (conjugate base), A-,
of the acid reacts with water and leaves free OH- in solution.
3.
If a strong acid reacts with a weak base, B, the resulting salt is an acidic
salt. The cation (conjugate acid), BH+,
of the base reacts with water and leaves free H+ in solution.
4. If a weak acid reacts with a weak base, the resulting salt could be neutral, acidic or basic depending on how weak the acid and base are in relation to each other.
You
can tell if a salt is neutral, acidic or basic by looking at the acid and base
that reacted to form the salt. Remember that a salt is made from the
positive metal ion (cation) of a base and the negative nonmetal ion (anion) of
an acid.
Solubility Equilibrium
A. In
a saturated solution of an ionic solid, an equilibrium exists between the ions
dissolved in solution and the excess solid which hasn’t dissolved and remains
in the crystal state.
B. An
insoluble solid dissolves to a limited extent in water solutions. The solid is dissolving at the same rate at
which the small number of dissolved ions are re-forming the crystal solid.
This
is called solution equilibrium.
C.
For the reaction: AB2(s) Ö
A+1(aq)
+ 2 B-1(aq) , the equilibrium expression is:
.
D.
Because AB2(s) is a solid, it’s concentration doesn’t change
and the equilibrium expression becomes
Keq.[
AB2(s)] = [A+1].[
B-1]2.
E. The
product of two constants is itself another constant. The new constant is called the
solubility
product constant, or the solubility product, and is symbolized by Ksp.
F.
The solubility product expression, also called the ion product, for the
above reaction is
Ksp
= [A+1].[ B-1]2.
G. Again
this is specified for a specific temperature because solubility’s vary with
temperature.
H. The
solubility of a insoluble salt is a measure of how much (in grams or moles)
will dissolve in a given amount of solution.
The concentration of the ions is based on the solubility and the
stoiciometric mole ratio between the salt and it’s ions as determined by a
balanced equation.
Saturated
solutions
1. insoluble salt ions in solution are in
equilibrium with the undissolved ionic solid
2. solubility product constant: Ksp, special case of equilibrium
constant, Keq
3. if
the concentrations, Q, > Ksp
the salt will not completely dissolve
if the concentrations,
Q, < Ksp the salt will
dissolve
Q is determined just
like Ksp, except the concentrations are not necessarily equilibrium
concentrations
4. if add common ion to saturated solution it
causes the precipitation of the solute (ionic solid)
5. solubility of substance decreases by the
addition of a common ion (LeChatelier)